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0 votes 1 answer Solve the following systems of simultaneous linear equations by the method of elimination by equating the coefficient 2x y = 13, 5x – 3y = 16 Solve the system of linear equations, using matrix method x – y 2z = 7; OMTEX CLASSES 3x – y = 2; 1 Using The Graphical Method Solve Each Of The Gauthmath 3x-y=2 2x-y=3 graphical method

You can put this solution on YOUR website!Question graph y = 2/3x3 Answer by jim_thompson5910 () ( Show Source ) You can put this solution on YOUR website!You can put in numbers to find which is the graph 3/2(2)^2 4(2) 2 = 4 Now you look for the graphs that have the point (2, 4) Only one graph has this which is graph 2 The answer is the second graph Hope this helps! Graph Of The Elliptic Curve Y 2 X 3 2x 2 On The Real Field R Download Scientific Diagram Y=2x-3 y=-3x+2 graph

Answered 4 years ago 1plot x^2 2invert it about x axis 3raise it upwards by 1 unit 4This is y=1x^2 5for mod (y), along with this, take mirror image about x axis 6Combined graph is the solution 7Restrict answer between y=1 and y=1 as maximum value of mod (y) is 1 38K viewsGraph y=x^22x1 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for Tap for more steps Use the form , to find the values of , , and Consider the vertex form of a parabolaSubtract 1 1 from − 8 8 Move the negative in front of the fraction Substitute the values of a a, d d, and e e into the vertex form a ( x d) 2 e a ( x d) 2 e Set y y equal to the new right side Use the vertex form, y = a ( x − h) 2 k y = a ( x h) 2 k, to determine the values of a Curve Sketching Graph y=x^4-2x^2-x-1

 Pick either one of the equations and make either x or y the subjects of the formula and substitute the value of either y or x into the other equation Ie " "x=32y" " (from first equation) Now substitute x above into second equation 2(32y)y=1 64yy=1 65y=1 5y=7 Therefore y=7/5 Now substitute the yvalue into the equation to find x 2x7/5=1 2x=5/5(=1) 7/5 x=1/5 Thus, xSolve by Substitution 3xy=2 , x2y=3 3x y = 2 3 x − y = 2 , x 2y = 3 x 2 y = 3 Subtract 2y 2 y from both sides of the equation x = 3 2ySolve by Addition/Elimination x2y=3 2x3y=9 x − 2y = 3 x 2 y = 3 2x − 3y = 9 2 x 3 y = 9 Multiply each equation by the value that makes the coefficients of x x opposite (−2)⋅ (x−2y) = (−2)(3) ( 2) ⋅ ( x 2 y) = ( 2) ( 3) 2x−3y = 9 2 x 3 y = 9 Simplify Tap for more steps Simplify ( − 2) ⋅ ( x − 2 y Solve 1 2 X 2y 5 3 3x 2y 3 2 5 4 X 2y 1 5 3x 2y 61 60 Mathematics Topperlearning Com 56o23roo X+2y=3/2 2x+y=3/2 by elimination method